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-144+225x^2=0
a = 225; b = 0; c = -144;
Δ = b2-4ac
Δ = 02-4·225·(-144)
Δ = 129600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{129600}=360$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-360}{2*225}=\frac{-360}{450} =-4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+360}{2*225}=\frac{360}{450} =4/5 $
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